Concrete Technology
Concrete Mix Design Grade M60
CONCRETE MIX DESIGN (GRADE M60)
(a) DESIGN STIPULATION:-
Target strength = 60Mpa
Max size of aggregate used = 12.5 mm
Specific gravity of cement = 3.15
Specific gravity of fine aggregate (F.A) = 2.6
Specific gravity of Coarse aggregate (C.A) = 2.64
Dry Rodded Bulk Density of fine aggregate = 1726 Kg/m3
Dry Rodded Bulk Density of coarse aggregate = 1638 Kg/m3
Max size of aggregate used = 12.5 mm
Specific gravity of cement = 3.15
Specific gravity of fine aggregate (F.A) = 2.6
Specific gravity of Coarse aggregate (C.A) = 2.64
Dry Rodded Bulk Density of fine aggregate = 1726 Kg/m3
Dry Rodded Bulk Density of coarse aggregate = 1638 Kg/m3
Step-1
Calculation for weight of Coarse Aggregate:
From ACI 211.4R Table 4.3.3 Fractional volume of oven dry Rodded C.A for 12.5mm size aggregate is 0.68m3
Weight of C.A = 0.68*1638 = 1108.13 Kg/m3
From ACI 211.4R Table 4.3.3 Fractional volume of oven dry Rodded C.A for 12.5mm size aggregate is 0.68m3
Weight of C.A = 0.68*1638 = 1108.13 Kg/m3
Step-2
Calculation for Quantity of Water:
From ACI 211.4R Table 4.3.4
Assuming Slump as 50 to 75mm and for C.A size 12.5 mm the Mixing water = 148 ml
Void content of FA for this mixing water = 35%
Void content of FA (V)
V = {1-(Dry Rodded unit wt / specific gravity of FA*1000)}*100
= [1-(1726/2.6*1000)]*100
= 34.62%Adjustment in mixing water = (V-35)* 4.55
= (34.62 – 35)*4.55
= -1.725 ml
Total water required = 148 + (-1.725) = 146.28 ml
Step-3
Calculation for weight of cement
From ACI 211.4R Table 4.3.5(b)
Take W / C ratio = 0.29
Weight of cement = 146.28 / 0.29 = 504.21 kg/m3
Assuming Slump as 50 to 75mm and for C.A size 12.5 mm the Mixing water = 148 ml
Void content of FA for this mixing water = 35%
Void content of FA (V)
V = {1-(Dry Rodded unit wt / specific gravity of FA*1000)}*100
= [1-(1726/2.6*1000)]*100
= 34.62%Adjustment in mixing water = (V-35)* 4.55
= (34.62 – 35)*4.55
= -1.725 ml
Total water required = 148 + (-1.725) = 146.28 ml
Step-3
Calculation for weight of cement
From ACI 211.4R Table 4.3.5(b)
Take W / C ratio = 0.29
Weight of cement = 146.28 / 0.29 = 504.21 kg/m3
Step-4
Calculation for weight of Fine Aggregate:Cement = 504.21 / 3.15*1000= 0.1616
Water = 146.28 / 1*1000= 0.1462
CA = 1108.13 / 3*1000= 0.3690
Entrapped Air = 2 / 100= 0.020
Total = 0.7376m3
Volume of Fine Aggregate= 1-0.7376
Weight of Fine Aggregate= 0.2624*2.6*1000= 683.24 kg/m3
Water = 146.28 / 1*1000= 0.1462
CA = 1108.13 / 3*1000= 0.3690
Entrapped Air = 2 / 100= 0.020
Total = 0.7376m3
Volume of Fine Aggregate= 1-0.7376
Weight of Fine Aggregate= 0.2624*2.6*1000= 683.24 kg/m3
Step-5
Super plasticizer:
For 0.8% = (0.8 / 100)*583.53 = 4.668 ml
For 0.8% = (0.8 / 100)*583.53 = 4.668 ml
Step-6
Correction for water:
Weight of water (For 0.8%) =146.28 – 4.668 =141.61 kg/m3Requirement of materials per Cubic meter
Cement = 504.21 Kg/m3
Fine Aggregate = 683.24 Kg/m3
Coarse Aggregate = 1108.13 Kg/m3
Water = 141.61 Kg/ m3
Super plasticizers = 4.6681 / m3
Cement = 504.21 Kg/m3
Fine Aggregate = 683.24 Kg/m3
Coarse Aggregate = 1108.13 Kg/m3
Water = 141.61 Kg/ m3
Super plasticizers = 4.6681 / m3
So the final ratio becomes
Cement : Fine agg (kg/m3) : Coarse agg (kg/m3) : Water (l/m3): Superplasticizer (l/m3)
1: 1.35 :2.19 :0.29 :0.8