Design of Stair Case
Vertical distance between two floors= 3.2 m
Assuming two flights
Height Of each flights= 3.2/2 = 1.6m
Clear Width Of each Step=1500mm
Rise Of each Step =150mm
Thread Of each Step=230mm
No of rise/flight=12
Going of each flight=12×230 = 2760mm
Width of Support=230mm
Grade of Concrete=M20
Grade of Steel =Fe415
SPAN OF STAIR CASE:
Clear Span=6m
Effective Span=6000+230 =6230mm
DESIGN OF FLIGHT:
Bearing of the flight = 150mm
Effective horizontal Span=6.075m
THICKNESS OF SLAB:
Considering 50mm Per m of Span
1.6×50=300mm
2.Dead load=230×25×1×1 = 5750N/m2
3.Finish=50×24=1200 N/m2 = 6950N/m2
Corresponding load/eq.moment of span
(R2+T2)/T)×L
Load/M =8297.41N/M
Waist slab&ceiling finish =8.300N/M
Dead load of slab =1/2×230×150×19=0.32KN/M
Live Load =4KN/M
Total Load =12.62KN/M
Factored Load =12.62×1.5=18.93KN/M
Factored load for 1.5M =18.93×1.6=30.288KN/M
MOMENT AND REACTION:
RA=50.19KN & RB=50.30KN
Moment @3.0M
50.3×3.0-(8.5×0.5×0.32)+(12.52×1×1.10)+(30.26×0.720)
M =95.68KNM
Mu=Mu limit
95.686 =0.138×20×1000×d2
d =186.18mm<200
TO GET AST:
Ast = 50×(1-1√1-(4.6/20)×(95.68×106/1000×2002))/(415/20))
=1.12%
Ast =1.12/100×1000×200 = 2240mm
No .of 16mm dia bars = 2240/(3.14(16)2/4) = 11 bars
DISTRIBUTION BARS
(0.12/100)×1000×200 =240mm2
Spacing of 6mm dia bars =(3.14(6)2/4)240×1000=120mmc/c
Provide 6 mm dia @ 120mmc/c as distribution steel
DESIGN OF LANDING:
Reaction from flight = Rb×1.5-(8,5×0.5)×0.5+(12.52×1) ×0.5
=68KNM
Mu = Mu limit
68×106 = 0.138×20×1000×d2
d = 157 < 200mm
Ast = 50×(1-1√1-(4.6/20)×(68×106/1000×2002))/(415/20))
=0.8%
Ast =0.8/100×1000×200=1600mm2
Spacing of 12 mm dia bars =(3.14(12)2/4)1600×1000= 70mm
Provide 12 mm dia @ 70mmc/c on landing
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