<\/p>\n
Since the formula to be derived is d^2\/162, assumed cross section is circular and the material is cylinder.<\/p>\n
Weight density of steel = 7850 kg\/m^3.<\/p>\n
Weight density = weight\/volume.
\nWeight = weight density x volume.
\nVolume of cylinder= \u03c0h d^2 \/4
\nh is the height of cylinder bar. = 1m
\nd is diameter in mm<\/p>\n
Volume = 3.14\/4 x d^2 x 10^-6.(converted mm to m two times for d)
\nVolume of cylindrical bar = (7.85 x 10^-7) d^2 cum
\nWeight of cylindrical bar
\n= 7850 x 7.85 x 10^-7 x d^2.
\n= 0.00616 x d^2
\n= d^2 \/(0.00616^-1)
\n= d^2\/162.3
\n~ d^2\/162
\nSince d’s unit is converted into the formula from mm to m, you can directly use the dia number to find out the weight per metre. For example:
\n25 mm dia bar:
\n625\/162 = 3.85 kg<\/p>\n","protected":false},"excerpt":{"rendered":"
To find : weight of steel per metre. Since the formula to be derived is d^2\/162, assumed cross section is circular and the material is cylinder. Weight density of steel = 7850 kg\/m^3. Formula: Weight density = weight\/volume. Weight = weight density x volume. Volume of cylinder= \u03c0h d^2 \/4 h is the height …<\/p>\n","protected":false},"author":2264,"featured_media":963,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"two_page_speed":[],"footnotes":""},"categories":[50],"tags":[28,65],"class_list":["post-249","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-reinforcement","tag-civil-engineering-calculation","tag-reinforcement"],"yoast_head":"\n