{"id":6033,"date":"2018-12-01T18:20:18","date_gmt":"2018-12-01T12:50:18","guid":{"rendered":"https:\/\/www.onlinecivilforum.com\/site\/?p=6033"},"modified":"2022-12-13T11:29:10","modified_gmt":"2022-12-13T05:59:10","slug":"bar-bending-schedule-of-one-way-slab","status":"publish","type":"post","link":"https:\/\/onlinecivilforum.com\/site\/bar-bending-schedule-of-one-way-slab\/","title":{"rendered":"Bar Bending Schedule of One way Slab"},"content":{"rendered":"<h2>Bar Bending Schedule of One way Slab<\/h2>\n<p>Here we calculate bar bending schedule of one way slab given in detailed explanation:<\/p>\n<p>Main Reinforcement bars we provide in the short span of the slabs and the distribution bars will along the longer span of the slab.<\/p>\n<p>For your better understanding,let\u2019s take this example.<\/p>\n<p>Suppose we have a one way slab,which having a length 5 m or width 2 m (clear span).The main bars will be 12 mm in diameter @100 mm c\/c spacing.The Distribution bars will be 8 mm in diameter @125mm c\/c spacing.The clear cover will be 25 mm(Top or Bottom) and the thickness of the slab is 150 mm.<\/p>\n<p>1.Calculate the quantity of steel?<\/p>\n<p>2.Calculate the weight of steel?<\/p>\n<p><img decoding=\"async\" width=\"1128\" height=\"305\" class=\"wp-image-6034\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image.png 1128w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-600x162.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-300x81.png 300w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-768x208.png 768w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-700x189.png 700w\" sizes=\"(max-width: 1128px) 100vw, 1128px\" \/><\/p>\n<h3>Given data:<\/h3>\n<p>Length = 5 m (5000 mm)<\/p>\n<p>Width = 2 m (2000 mm)<\/p>\n<p>Main Bar = 12 mm @ 100 mm c\/c<\/p>\n<p>Distribution Bar = 8 mm @ 125 mm c\/c<\/p>\n<p>Clear cover = 25 mm from (Top and Bottom)<\/p>\n<p><span style=\"color: #0000ff;\"><strong><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/onlinecivilforum.com\/site\/calculation-of-brick-work-quantity\/\" aria-label=\"\u201cCalculation of Brick Work Quantity\u201d (Edit)\">Calculation of Brick Work Quantity<\/a><\/strong><\/span><\/p>\n<h3>Solution:<\/h3>\n<p>The quantity is done into two steps.<\/p>\n<p>1.Calculation of number of bars<\/p>\n<p>2.Cutting length of bars<\/p>\n<p>Step 1:Calculation of bars no\u2019s<\/p>\n<p>First calculate the number of bars required (main and distribution both).<\/p>\n<h3>Formula:<\/h3>\n<p>= (Total length \u2013 clear cover)\/center to center spacing + 1<\/p>\n<h3>Main bar:<\/h3>\n<p>= (5000 \u2013 (25+25))\/100 + 1<\/p>\n<p>= 4950 \/ 100 + 1<\/p>\n<p>= 51 bars<\/p>\n<h3>Distribution bar:<\/h3>\n<p>= (2000 \u2013 ( 25 + 25))\/125 + 1<\/p>\n<p>= 1950\/125+1<\/p>\n<p>= 17 bars<\/p>\n<h3>Step 2.Cutting Length<\/h3>\n<h4>Main Bar:<\/h4>\n<h4>Formula<\/h4>\n<p>= (L) + (2 x Ld) + (1 x 0.42D) \u2013 (2 x 1d)<\/p>\n<h4>Where<\/h4>\n<p>L = Clear span of the slab<\/p>\n<p>Ld = Development Length which is 40d ( where d is diameter of bar)<\/p>\n<p>0.42D = Inclined length (Bend length)<\/p>\n<p>1d = 45 degree bends (d is diameter of bar)<\/p>\n<p><strong><a class=\"row-title\" href=\"https:\/\/onlinecivilforum.com\/site\/bar-bending-schedule-of-column\/\" aria-label=\"\u201cBar Bending Schedule of Column\u201d (Edit)\">Bar Bending Schedule of Column<\/a><\/strong><\/p>\n<p><img decoding=\"async\" width=\"738\" height=\"300\" class=\"wp-image-6035\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-1.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-1.png 738w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-1-600x244.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-1-300x122.png 300w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2018\/12\/word-image-1-700x285.png 700w\" sizes=\"(max-width: 738px) 100vw, 738px\" \/><\/p>\n<h4>First calculate the length of \u201cD\u201d<\/h4>\n<p>= (Thickness) \u2013 2 (clear cover at Top,Bottom) \u2013 Diameter of the bar<\/p>\n<p>= 150 \u2013 2(25) \u2013 12<\/p>\n<p>= 88 mm<\/p>\n<p>By putting values<\/p>\n<h3>Cutting Length:<\/h3>\n<p>= 2000 + (2 x 40 x 12) + (1 x 0.42 x 88) \u2013 (2 x 1 x 12)<\/p>\n<p>= 2000 + 960 + 36.96 \u2013 24<\/p>\n<p>= 2972.96 mm or 2.973 m<\/p>\n<h3>Distribution Bar:<\/h3>\n<p>= Clear span + ( 2 x Development length (Ld))<\/p>\n<p>= 5000 + (2 x 40 x 8)<\/p>\n<p>= 5640 mm or 5.64 m<\/p>\n<p><strong><a class=\"row-title\" href=\"https:\/\/onlinecivilforum.com\/site\/bar-bending-schedule-of-beam\/\" aria-label=\"\u201cBar Bending Schedule of Beam\u201d (Edit)\">Bar Bending Schedule of Beam<\/a><\/strong><\/p>\n<h3>Conclusion:<\/h3>\n<h3>1.Main Bar:<\/h3>\n<p>= 51 nos<\/p>\n<h4>Length:<\/h4>\n<p>= 51 x 2.973 m<\/p>\n<p>= 151.623 m<\/p>\n<h4>Weight:<\/h4>\n<p>= (D2\/162) x length<\/p>\n<p>= 134.776 kg<\/p>\n<h3>2.Distribution Bar:<\/h3>\n<p>= 17 nos<\/p>\n<p>Note: The weight of the bar may vary depending upon the properties of the steel.<\/p>\n<p><strong><a class=\"row-title\" href=\"https:\/\/onlinecivilforum.com\/site\/bar-bending-schedule-of-column-footing\/\" aria-label=\"\u201cBar Bending Schedule of Column Footing\u201d (Edit)\">Bar Bending Schedule of Column Footing<\/a><\/strong><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Bar Bending Schedule of One way Slab Here we calculate bar bending schedule of one way slab given in detailed explanation: Main Reinforcement bars we provide in the short span of the slabs and the distribution bars will along the longer span of the slab. For your better understanding,let\u2019s take this example. Suppose we have &hellip;<\/p>\n","protected":false},"author":2264,"featured_media":6036,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"two_page_speed":[],"footnotes":""},"categories":[26],"tags":[136],"class_list":["post-6033","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-gendral-civil-engineering","tag-bar-bending-schedule"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Bar Bending Schedule of One way Slab<\/title>\n<meta name=\"description\" content=\"Bar Bending Schedule of One way Slab Here we calculate bar bending schedule of one way slab given in detailed explanation\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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