{"id":7864,"date":"2022-07-31T11:14:59","date_gmt":"2022-07-31T05:44:59","guid":{"rendered":"https:\/\/www.onlinecivilforum.com\/site\/?p=7864"},"modified":"2022-12-13T11:28:05","modified_gmt":"2022-12-13T05:58:05","slug":"design-and-calculation-of-reinforced-column","status":"publish","type":"post","link":"https:\/\/onlinecivilforum.com\/site\/design-and-calculation-of-reinforced-column\/","title":{"rendered":"Design and Calculation of Reinforced Column"},"content":{"rendered":"<h1><strong>Design and Calculation of Reinforced Column <\/strong><\/h1>\n<p><strong>The building shown has 3 storeys for Design and Calculation of Reinforced Column<\/strong><\/p>\n<p><img decoding=\"async\" width=\"243\" height=\"484\" class=\"wp-image-7865 aligncenter\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-1.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-1.png 243w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-1-151x300.png 151w\" sizes=\"(max-width: 243px) 100vw, 243px\" \/><\/p>\n<p><strong>1.Calculation of Load on Column<\/strong><\/p>\n<p>Load influence area on column B2(i.e.tributory area)<\/p>\n<p>= (3.70\/2 + 3.70\/2) (6.0\/2 + 6.0\/2) = 22m<sup>2 <\/sup><\/p>\n<p>Load on column B2 due to 1<sup>st<\/sup> storey<\/p>\n<p>= 22.0 x 12 = 264 KN<\/p>\n<p>(Area)x(Coef. As per table-1 of previous page)<\/p>\n<p>Total load on column B2 = 792 KN say 800 KN<\/p>\n[Due to 3 storeys (264&#215;3)]<img decoding=\"async\" class=\"aligncenter wp-image-7866\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-2.png\" alt=\"Calculation of Reinforced Column\" width=\"632\" height=\"881\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-2.png 632w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-2-600x836.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-2-215x300.png 215w\" sizes=\"(max-width: 632px) 100vw, 632px\" \/><\/p>\n<p><strong>2.Design of Column<\/strong><\/p>\n<p>Load on Column = 800 KN<\/p>\n<p>Concrete grade = M20(say)<\/p>\n<p>As per table-3,for 230 mm 450mm size,<\/p>\n<p>If 1.40% of steel is provided,<\/p>\n<p>If\u2019s load carrying capacity = 813 KN (&gt;800 KN)<\/p>\n<p>Hence ok<\/p>\n<p><strong>Buy Now <a href=\"https:\/\/onlinecivil.myinstamojo.com\/product\/3205026\/column-bar-bending-schedule-in-excel-format\/\">Column bar bending schedule in excel format<\/a><\/strong><\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-7867\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-3.png\" alt=\"Calculation of Reinforced Column\" width=\"626\" height=\"875\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-3.png 626w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-3-600x839.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-3-215x300.png 215w\" sizes=\"(max-width: 626px) 100vw, 626px\" \/><\/p>\n<p>Steel area = (1.4\/100) x 230 x 450 = 1449 mm<sup>2<\/sup><\/p>\n<p>Hence provide 8 nos of 16mm dia bars (ref. table-2 also)<\/p>\n<p>Lateral ties(rings)<\/p>\n<p>Provide 8 mm diameter rings @ 8\u201d c\/c<\/p>\n<p><img decoding=\"async\" width=\"652\" height=\"941\" class=\"wp-image-7868 aligncenter\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-4.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-4.png 652w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-4-600x866.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-4-208x300.png 208w\" sizes=\"(max-width: 652px) 100vw, 652px\" \/><\/p>\n<p><strong>Design of Column without Table in Hand<\/strong><\/p>\n<p>For M20 concrete &amp; Fe 415 steel,<\/p>\n<p>Load Carrying Capacity of Column with 2% reinft = (0.90) Cross section Area of concrete in \u201ccm<sup>2\u201d <\/sup><\/p>\n<p>Therefore Load Carrying Capacity of (300&#215;300) column with 2% reinft = 0.90 x 30 x 30 = 810 KN<\/p>\n<p>Hence ok (&gt;800KN)<\/p>\n<p>Size of Column : 300 x 300mm<\/p>\n<p>Reinforcement = 2% = (2\/100) x 30 x 30 = 18 c m<sup>2<\/sup><\/p>\n<p>Hence Provide (4Nos \u2013 20mm dia + 4 Nos \u2013 16mm dia)<\/p>\n<p><img decoding=\"async\" width=\"616\" height=\"870\" class=\"wp-image-7869 aligncenter\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-5.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-5.png 616w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-5-600x847.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-5-212x300.png 212w\" sizes=\"(max-width: 616px) 100vw, 616px\" \/><\/p>\n<p><img decoding=\"async\" width=\"642\" height=\"888\" class=\"wp-image-7870 aligncenter\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-6.png\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-6.png 642w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-6-600x830.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-6-217x300.png 217w\" sizes=\"(max-width: 642px) 100vw, 642px\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-7871\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-7.png\" alt=\"load carrying capacity m30\" width=\"638\" height=\"886\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-7.png 638w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-7-600x833.png 600w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-7-216x300.png 216w\" sizes=\"(max-width: 638px) 100vw, 638px\" \/><\/p>\n<p><strong>Safe load carrying of column based on % of steel and known column section for various grade of concrete and steel for Design and Calculation of Reinforced Column<br \/>\n<\/strong><\/p>\n<table>\n<tbody>\n<tr>\n<td>Steel Grade<\/td>\n<td rowspan=\"2\">Fe 415<\/td>\n<td rowspan=\"2\">Fe 500<\/td>\n<\/tr>\n<tr>\n<td>Concrete Grade<\/td>\n<\/tr>\n<tr>\n<td>M20<\/td>\n<td>P = (2.7005 p + 8) bD\/1500<\/td>\n<td>P = (3.27p + 8) bD\/1500<\/td>\n<\/tr>\n<tr>\n<td>M25<\/td>\n<td>P = (2.6805 p + 10) bD\/1500<\/td>\n<td>P = (3.25p + 10) bD\/1500<\/td>\n<\/tr>\n<tr>\n<td>M30<\/td>\n<td>P = (2.6605 p + 12) bD\/1500<\/td>\n<td>P = (3.23p + 12) bD\/1500<\/td>\n<\/tr>\n<tr>\n<td>M35<\/td>\n<td>P = (2.6405 p + 14) bD\/1500<\/td>\n<td>P = (3.21p + 14) bD\/1500<\/td>\n<\/tr>\n<tr>\n<td>M40<\/td>\n<td>P = (2.6205 p + 16) bD\/1500<\/td>\n<td>P = (3.19p + 16) bD\/1500<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Where P is Axial Load carrying capacity of column in KN.<\/p>\n<p>P = % of steel reinforcement (say 2 % is 2)<\/p>\n<p>b = Breadth of Column in mm<\/p>\n<p>D = Depth of Column in mm<\/p>\n<p><strong>See More <a href=\"https:\/\/onlinecivilforum.com\/site\/category\/structural\/\">Structural Design<\/a><\/strong><\/p>\n<p><img decoding=\"async\" class=\"wp-image-7872 aligncenter\" src=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-8.png\" alt=\"concrete reinforcement\" width=\"426\" height=\"300\" srcset=\"https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-8.png 426w, https:\/\/onlinecivilforum.com\/site\/wp-content\/uploads\/2022\/07\/word-image-7864-8-300x211.png 300w\" sizes=\"(max-width: 426px) 100vw, 426px\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Design and Calculation of Reinforced Column The building shown has 3 storeys for Design and Calculation of Reinforced Column 1.Calculation of Load on Column Load influence area on column B2(i.e.tributory area) = (3.70\/2 + 3.70\/2) (6.0\/2 + 6.0\/2) = 22m2 Load on column B2 due to 1st storey = 22.0 x 12 = 264 KN &hellip;<\/p>\n","protected":false},"author":2264,"featured_media":7874,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"two_page_speed":[],"footnotes":""},"categories":[54],"tags":[91,109,102],"class_list":["post-7864","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-design-spreadsheets","tag-building-construction","tag-requirement","tag-structural-design"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Design and Calculation of Reinforced Column<\/title>\n<meta name=\"description\" content=\"Design and Calculation of Reinforced Column The building shown has 3 storeys Calculation of Load on Column\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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